package com.future.leetcode.string;

/**
 * 编写一个函数，其作用是将输入的字符串反转过来。输入字符串以字符数组 char[] 的形式给出。
 * 不要给另外的数组分配额外的空间，你必须原地修改输入数组、使用 O(1) 的额外空间解决这一问题。
 * 你可以假设数组中的所有字符都是 ASCII 码表中的可打印字符。
 * <p>
 * 示例 1：
 * 输入：["h","e","l","l","o"]
 * 输出：["o","l","l","e","h"]
 * 示例 2：
 * 输入：["H","a","n","n","a","h"]
 * 输出：["h","a","n","n","a","H"]
 * <p>
 * 链接：https://leetcode-cn.com/problems/reverse-string
 */
public class ReverseString2 {
    public void reverseString(char[] s) {
        for (int l = 0, r = s.length - 1; l < r; l++, r--) {
            char tmp = s[l];
            s[l] = s[r];
            s[r] = tmp;
        }
    }

}
